Question

A bullet of mass 40 gram fired with a velocity 150 m from a pistol of mass 1kg what is the recoil velocity of the Pistol
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Answer 1

Answer:

6m/ s

explanation

we know that according to conservation of momentum

pi= pf

so, 40g × 150m/s =1kg×v

40÷1000kg × 150m/s×v

v= 6m/s