Physics, asked by dadu1739, 1 year ago

A bullet of mass 40 kg jas its K.E equal to 200J.Find the speed of the bullet

Answers

Answered by aaryansinghani22
2

K.E.=1/2mv^2

200=1/2×40×v^2

v^2=200×2/40

v^2=10

v=root10 m/s

=3.16m/s

Thank You

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