Question

A bullet of mass 40g is fired horizontally with a velocity of 150 ms-1 from a pistol of mass 5 kg. Calculate the recoil velocity of the pistol.​

Answer 1

Answer:

Initial momentum of the system is 0 as it is at rest.

After firing-

MV=mv

⟹V=

$\frac{mv}{m}$

=

$\frac{0.02 \times 150}{2}$

⟹V=1.5m/s

Hope it helps you

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