Question

a bullet of mass 40g is horizontally fired with a horizontal velocity 150m/s from a pistol of mass 5kg.what is the recoil velocity of the pistol?​

Answer 1

Answer:

v = -0.4 m/s

Explanation:

It is given that,

Mass of the bullet, m = 40 g = 0.04 kg

Speed of the bullet, v = 20 m/s

Mass of the pistol, m' = 2 kg

Let p is the initial momentum of the system and p' is the final momentum. The initial momentum of the bullet + pistol is equal to zero because they both are at rest.

When the bullet is fired, final momentum is given by :

According to the conservation of momentum,

v = -0.4 m/s

So, the recoil velocity of the pistol is 0.4 m/s. Hence, this is the required solution.

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