Question

a bullet of mass 40g is horizontally fired with a velocity of 20m/s from a pistol of mass 2kg .What is the recoil velocity of the pistol

Answer 1

Hey friend . Your question can be answered in the following way. Check out the example attached below to get an idea about the question.

Answer 2

Answer:

v = -0.4 m/s

Explanation:

It is given that,

Mass of the bullet, m = 40 g = 0.04 kg

Speed of the bullet, v = 20 m/s

Mass of the pistol, m' = 2 kg

Let p is the initial momentum of the system and p' is the final momentum. The initial momentum of the bullet + pistol is equal to zero because they both are at rest.

When the bullet is fired, final momentum is given by :

$p'=0.04\times 20+2\times v$

According to the conservation of momentum,

$0=0.04\times 20+2\times v$

v = -0.4 m/s

So, the recoil velocity of the pistol is 0.4 m/s. Hence, this is the required solution.