Question

a bullet of mass 40kg traveling with a velocity of 18m/s penetrates a thin wall and is brought to rest in 0.06s. find the depth of penetration and the average retarding force of the wall

Answer 1

Hi! here is your answer

final velocity v = 0

final velocity v = 0initial velocity u = 400m/s

v*2-u*2 = 2as

16000m*2/s*2 = 2a 0.1m

a=80000m/s*2

f=0.03kg x 8000n

f=24000n

Hope it helpss

Answer 2

Answer:

v=u-at

when the bullet hits the wall,the final velocity becomes zero

so v=0,u=18m/s

as v=u-at

a=-300m/s^2

v^2-u^2=2as

s=,0.54m

RETARDING FORCE=-12000kgm/s^2