A bullet of mass 4g when fired with a velocity of 50 m/s , can enter a wall up to a depth of 10 cm. How much will be the average resistance afferred by the wall
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Answer:
Thus, the wall applies 50N force to resist the motion of the bullet.
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Explanation:
Question:−
A bullet of mass 4g fired with a velocity of 50 m/s enters a wall up to a depth of 10 cm. Calculate the average resistance offered by the wall
Given:-
➠Mass of the bullet, u = 4 g = 4 × 10⁻³ kg
➠Initial velocity, u = 50 m/s
➠Distance, S = 10 cm = 10 × 10⁻² m
➠Final velocity, v = 0 (since bullet comes to rest finally)
To Calculate:-
Force, F = ??
Formula To Be used:-
F = ma
(or) F = m × (v² - u²/2S)
v² - u² = 2aS
a = v² - u²/2S
Solution:-
F = 4 × 10⁻³ × [(0)² - (50)²/2 × 10 × 10²]
F = 4 × 10⁻³ [- 2500 × 10²/2 × 10]
F = - 50 N.
➠ Hence, the average resistances offered by the wall - 50 N.
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