Question

A bullet of mass 4g when fired with a velocity of 50 m/s , can enter a wall up to a depth of 10 cm. How much will be the average resistance afferred by the wall

Answer 1

Answer:

Thus, the wall applies 50N force to resist the motion of the bullet.

Hope it helps u !!!!

Answer 2

Explanation:

Question:−

A bullet of mass 4g fired with a velocity of 50 m/s enters a wall up to a depth of 10 cm. Calculate the average resistance offered by the wall

Given:-

➠Mass of the bullet, u = 4 g = 4 × 10⁻³ kg

➠Initial velocity, u = 50 m/s

➠Distance, S = 10 cm = 10 × 10⁻² m

➠Final velocity, v = 0 (since bullet comes to rest finally)

To Calculate:-

Force, F = ??

Formula To Be used:-

F = ma

(or) F = m × (v² - u²/2S)

v² - u² = 2aS

a = v² - u²/2S

Solution:-

F = 4 × 10⁻³ × [(0)² - (50)²/2 × 10 × 10²]

F = 4 × 10⁻³ [- 2500 × 10²/2 × 10]

F = - 50 N.

➠ Hence, the average resistances offered by the wall - 50 N.