.A bullet of mass 4g when fired with a velocity of 50m/s,can enter a wall up to a depth of 10cm.How much will be the average resistance offered by the wall?
Answers
Answered by
364
Thus, the wall applies 50N force to resist the motion of the bullet.
hope it helps....
hope it helps....
Attachments:
Answered by
100
Given:
Mass of the Bullet = 0.004 kg
Initial Velocity = u = 50 m/s
Depth = s = 10cm = 0.1 m
To find:
Average resistance offered by the wall
Solution:
Final velocity = 0
According to the equation of velocity
v² - u² = 2as
a = (0 - 2500) / 2 x 0.1
a = - 2500/ 0.2
= - 1250
Now,
F = ma
F = 0.004 x -1250
= - 50N
Answer: Force Exerted by wall on Bullet is +50N ( Newton's third law)
Similar questions