Question

a bullet of mass 4g when fired with a velocity of 50m/s, can enter a wall upon a depth pf 10cm. How much will be the average resistance offered by the wall?

....please answer with step by step explanation....I need ur help​

Answer 1

Answer:

The resistance offered by the wall is 50N.

Explanation:

The reason is to stop 50N force the wall must apply the same magnitude of force.

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Answer 2

The average resistance offered by the wall is 50N.

Given:

Mass (m)  = 4g = 0.004kg

Initial velocity (u) = 50m/s

Final velocity(v) = 0m/s

Depth of wall (s)  = 10cm = 0.1m

To find: Average resistance offered by wall

Solution:

2as = $v{2} - u^{2}$

2 * a* 0.1 = $0^{2} - 50^{2}$

a * 0.2 = -2500

a = -2500/0.2

a = -12,500 m/$s^{2}$

F = ma

F= 0.004 * (-12,500)

F = - 50N

So, the force required is 50N. Negative sign means that force is applied in opposite direction.

Hence, the average resistance offered by the wall is 50N.

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