A bullet of mass 5 g is fired from a gun weighing 5.0 kg. If the initial velocity of the bullet is 250 m s–1, calculate the velocity with which the gun recoils.
Answers
Answer:
Given:
Mass of gun = 5 kg
Mass of bullet = 5 g
Velocity of bullet = 250 m/s
To find:
Recoil Velocity of gun
Calculation:
Whenever the trigger of gun is pressed , the bullet leaves the muzzel of the gun with high velocity. Since the momentum pf the system is conserved , the gun experiences equal momentum change in the opposite direction.
Hence the gun recoils backwards. The velocity is called Recoil Velocity
Calculation:
As per Conservation of Momentum :
Initial Momentum = Final momentum
So final answer :
Negative sign indicates opposite direction or recoil as compared to velocity of bullet.
Question :
A bullet of mass 5 g is fired from a gun weighing 5.0 kg. If the initial velocity of the bullet is 250 m s–1, calculate the velocity with which the gun recoils.
Theory :
Conservation of linear momentum :
If no external force acts on the system of constant mass the total momentum of the system remains constant .
Solution :
Let recoil velocity = v
Given :
bullet mass,m =5g = 0.005 kg
intital velocity,u = 250 m/s
Mass of Gun ,M = 5kg
Intital both bullet and gun are at rest
⇒Intial momentum before firing = 0
______________________________
As no external force acts on the system
So According to the law of conservation of Momentum .
Total momentum before firing = Total momentum after the firing
⇒0 = mu+ Mv
⇒Mv = -mu
⇒5× v = -0.005×250
Therefore;
⇒The negative sign shows that v and u are in opposite directions i.e ,the gun gives a kick in the backward direction or gun recoils with velocity v.