Question

A bullet of mass 5 g leaves a rifle with a velocity of 2 m/s . If it strike a wooden target and panatrates 20 cm into it , what is the average resistance offered by the target

Answer 1

Given :

Mass of bullet , m = 5 g = 0.005 kg .

Velocity of bullet , v = 2 m/s .

To Find :

If it strike a wooden target and penetrates 20 cm into it , what is the average resistance offered by the target .

Solution :

We know , acceleration is given by :

$v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{0-2^2}{2\times 0.2}\\\\a=-10\ m/s^2$

So , the average resistance offered by the target is :

$F=ma\\\\F=0.005\times 10\ N\\\\F=0.05 \ N$

Hence , this is the required solution .

Learn More :

Kinematics

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