Science, asked by rpgsachu2006, 1 year ago

A bullet of mass 5 g travelling at a speed of 120 m/s penetrates deeply into a fixed target and is brought to rest in 0.01 seconds. Calculate a) the distance of penetration in the target b)average force exerted on the bullet

Answers

Answered by pinjaraarifisha

Answer:

u = 120 m/s

v = 0

t = 0.01 s

a = (v-u)/ t = -120 / 0.01 = -12000 m/s

a) S = (v² - u²)/2a = -120² / 2*(-12000) = 120 / 200 = 0.6 m

distance of penetration is 0.6m

b) force = ma = 0.005×12000 = 60N

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