A bullet of mass 50 g is fired from a stationary rifle
into a wooden block of mass 1.95 kg placed on a
horizontal wooden surface. On striking, the bullet
is embedded into the block and both together cover
a distance of 200 m in a straight path before coming
to rest. Given the coefficient of friction between the
block and the surface is 0.2 and the mass of the rifle
from which the bullet is triggered is 14 kg, find the
magnitude of the velocity of the recoil of the rifle.
(Neglect the resistance of air on the bullet).
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Mass of the bullet is m
b
=50gm=0.05Kg
Initial velocity of bullet u
b
=100m/s
Final velocity is v
b
=0m/s
(1) Initial momentum of bullet p
i
=m
b
u
b
=5Kgm/s
(2) Final momentum of bullet p
f
=m
b
v
b
=0.05×0=0
(3) Retardation occurred by the wooden block is
v
2
−u
2
=2as
−(100)
2
=2a(0.02)
a=−250000m/s
2
(4) Resistive force
F=ma
=0.05×−250000
=12500N
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