Question

A bullet of mass 50 g is fired horizontally with a velocity 200 m/s from a pistol of mass 5 kg.
Calculate the recoil velocity of the pisto​

Answer 1

Given :

• mass of bullet, m₁ = 50 g = 50/1000 kg = 0.05 kg

• Since bullet will be at rest initially therefore, initial velocity of bullet, u₁ = 0

• final velocity of bullet, v₁ = 200 m/s

• mass of pistol, m₂ = 5 kg

• initially pistol will be at rest, therefore, initial velocity of pistol, u₂ = 0

To find :

• recoil velocity of pistol, i.e, final velocity of pistol, v₂ = ?

Knowledge required :

        Formula to calculate momentum

•            momentum = mass × velocity

         Law of conservation of momentum

•       Law of conservation of momentum says that during a collision between            two objects the total momentum of the system before collision is equal to the total momentum of the system after collision.

that means, the momentum of an isolated system remains constant.

   → m₁ u₁ + m₁ u₂ = m₁ v₁ + m₂ v₂

[ where m₁ and m₂ are masses, u₁ and u₂ are initial velocities , v₁ and v₂ are final velocities of two objects respectively ]

Calculation :

Using law of conservation of momentum

→ m₁ u₁ + m₁ u₂ = m₁ v₁ + m₂ v₂

→ (0.05) (0) + (5) (0) = (0.05) (200) + (5) v₂

→ 0 = 10 + 5 v₂

→ - 10 = 5 v₂

→ v₂ = -10 / 5

→ v₂ = -2  m/s

Therefore,

• Recoil velocity of the Pistol is -2 m/s .

(negative sign with velocity represent that Pistol will recoil in opposite direction to the motion of bullet)

Answer 2

Answer:

2m/s

Explanation:

hope it help you