Question

A bullet of mass 50 g is horizontally fired with a velocity of 200m/s from a pistal of mass5kg what is recoil velocity of the pistal

Answer 1

Answer:

-2m/s

Explanation:

Given,

Mass of bullet(m)=50g⇒0.05 kg

Velocity=200m/s

Mass of pistol(M)=5 kg

Now, Recoil velocity(Vr)=-mv/M

Vr=-(0.05)(200)/5

Vr=-10/5

Vr=-2 m/s

Negative sign indicates that recoil velocity is acting opposite to the direction of motion.

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