a bullet of mass 50 g is moving with a velocity of 500 m/s. It penetrates 10 cm into a still target and comes to rest.
1) Calculate the kinetic energy possessed by the bullet
2)and the average retarding force offered by the target.
* NO STUPID ANSWERS WILL BE APPRECIATED.
* WRONG ANSWERS WILL BE REPORTED.
*BEST ANSWER WILL BE MARKED AS THR BRAINIEST.
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Hi..
Retarding force
m = 50 g = 50 × 10-3 kg, u = 500 ms-1, s = 10 cm, v = 0
(i) KE = 1/2×mv2 = 1/2×50 × 10-3 × (500)2 = 6250 J.
(ii) Using v2 + u2 = 2aS, we get
a = {v2 + u2}/{2aS} = {02 (500)2}/{2 × 10 ×10-2}
= 1250000ms-2.
Therefore, retarding force, F = ma = 50 × 10-3 × 1250000 = 62500 N. ...
Hope this helps u!!
Retarding force
m = 50 g = 50 × 10-3 kg, u = 500 ms-1, s = 10 cm, v = 0
(i) KE = 1/2×mv2 = 1/2×50 × 10-3 × (500)2 = 6250 J.
(ii) Using v2 + u2 = 2aS, we get
a = {v2 + u2}/{2aS} = {02 (500)2}/{2 × 10 ×10-2}
= 1250000ms-2.
Therefore, retarding force, F = ma = 50 × 10-3 × 1250000 = 62500 N. ...
Hope this helps u!!
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