Question

A bullet, of mass 50 g moving at 400 m.s-1, penetrates 20 cm
into a wall and stops. Find the average resistance offered by
the wall.
[Ans. 20000 N]
​

Answer 1

Answer: here, u= 400 m/s. V= 0 m/s. S= 20cm =0.2 m

Now from the equation , v^2 = u^2 - 2aS

0 = (400)^2 -2a ×0.2

a= 4,00,000 m/s^2

Now we know ,F = ma

F=( 50÷1000 ) N =20,000 N

Explanation: