Question

A bullet of mass 50 g moving at 400 mcdot s^(-1) penetrates a wall with an average force of 4xx 10 ^(4) N. It comes out of the other side of the wall at 50 mcdot s^(-1). Find the thickness of the wall. Another bullet of comparatively lower mass, moving with the same velocity cannot penetrate the same wall. What can be the maximum mass of the bullet?

Answer 1

Answer:

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Explanation:

Mass of the bullet is mb=50gm=0.05Kg

Initial velocity of bullet ub=100m/s

Final velocity is vb=0m/s

(1) Initial momentum of bullet pi=mbub=5Kgm/s

(2) Final momentum of bullet pf=mbvb=0.05×0=0

(3)  Retardation occurred by the wooden block is

v2−u2=2as

−(100)2=2a(0.02)

a=−250000m/s2

(4) Resistive force

F=ma

=0.05×−250000

=12500N