Question

A bullet of mass 50 g travelling with a speed of 15ms penetrates into a
bag of sand and is uniformly brought to rest in 0.05.
Find (a) How for the bullet will penetrate into the bag of sand?
(b) The average force exerted by the sand?​

Answer 1

Explanation:

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Answer 2

Answer:

Please find the answer below.

Explanation:

m= 0.050kg

v = 0ms^-1 , u = 15ms^-1

T=0.05sm                         a= v-u/t = -300ms^-1

(a) using v^2-u^2=2as

s = -225/600

   = 0.375m

(b) F = ma

       = 0.050*-300

       =15.0 N