A bullet of mass 50 gram is fired from a gun of mass 3 kilograms recoils backward velocity of gun is 2 metre per second find the velocity of the bullet
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Let the mass of the bullet be m1 =50g or 0.05 kg
mass of the gun be m2= 3kg
Velocity of the bullet be v1 = x
velocity of the gun be v2= 2 m/s
Therefore, the formula that will be used in this question would be:
m1 v1 = m2 v2
0.05^x = 3^ 2
x = 3^2/0.05
x =120 m/s
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