Question

a bullet of mass 50 gram is fired with a velocity of 100m/s penetrates 10 cm inside the block before coming to rest find the force experienced by the bullet
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Answer 1

Explanation:

Mass of bullet= 50g = 0.5kg

Initial velocity= 100m/s

Final velocity= 0m/s

Distance penetrate inside the block= 10cm = 0.1m

Let acceleration be a

Now,

From the 3rd law of motion we know that,

2as = v²-u²

=>2×a×0.1=0²-100²

=>0.2a=-10000

=>a. =10000×10/2

=>a. = 50000

Hence,the acceleration of the bullet is 50000m/sec²

Now,

As we know that,

F=ma

So,

F=0.5×50000

= 25000N

(Solved)