Question

a bullet of mass 50 gram movving with an initial velocity 100m/s , syrikes a wooden box and comes to rest after penetrating 2 cm of distance

find retardation
find intial and final momentum
and find resistive force exerted by wooden box




plz helppp .... i need the solution badly
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Answer 1

Answer:

Mass of the bullet is m

b

=50gm=0.05Kg

Initial velocity of bullet u

b

=100m/s

Final velocity is v

b

=0m/s

(1) Initial momentum of bullet p

i

=m

b

u

b

=5Kgm/s

(2) Final momentum of bullet p

f

=m

b

v

b

=0.05×0=0

(3) Retardation occurred by the wooden block is

v

2

−u

2

=2as

−(100)

2

=2a(0.02)

a=−250000m/s

2

(4) Resistive force

F=ma

=0.05×−250000

=12500N