Question

A bullet of mass 50 gram travelling at 500 metre second penetrates under cm into a wooden block find the average force exerted on the block​

Answer 1

The average force exerted on the block is 0.625 × 10⁴ N.

Given -

• Mass of bullet = 50 gram
• Initial velocity of the bullet = 500 m/sec
• Distance covered by the bullet in a wooden block = 100 cm = 1 m
• Final velocity of the bullet will be zero

We know that -

v² - u² = 2as

By substituting the value we get

0 - (500)² = 2 × a × 1

a = - 125000 m/s²

The average force exerted on the block is

F = ma

F = 0.05 × 125000

F =  0.625 × 10⁴ N