Question

A bullet of mass 50 gram travelling with a speed of 15 meter per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second find how for the bullett will penetrate into the bag of sand and find the average force exerted by the sand?

Answer 1

U=15m/s

V=0m/s

T=0.05sec

a=(v-u)/t

a=-15/0.05=-300

V^2-u^2=2as

-225=2x(-300)xS

S=3/8m=0.375m

Force=mass x acceleration

=50/1000 x -300=-15N