Question

A bullet of mass 50g is fired from a gun at a speed of 250ms. What is the kinetic energy possessed by the bullet?

Answer 1

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Answer 2

Answer:

K.E = $\frac{1}{2}mv^{2}$

m = 0.05 kg

v = 250 m/s

So, KE = $\frac{1}{2} (0.05)(250)^{2}$

= 1562.5 Joule