Question

A bullet of mass 50g is fired from a gun of mass 10kg with a velocity 60m/s . calculate the recoil velocity of gun​

Answer 1

Answer:

momentum after = momentum before MV=mv ,10V=0.05×60,=10V=3,V=3/10=0.3 m/s

Answer 2

Answer:

Answer:

Speed of recoil = 0.3m/s

Concept:

Apply law of conservation of Linear Momentum. That is, momentum of bullet equals the momentum of gun.

Explanation:

Mass of bullet (mb) = 50g = 0.05Kg

Mass of gun (mg) = 10kg

Let speed of recoil of gun be 'v'.

Speed of bullet (vb) = 60m/s (average bullet speed)

Applying law of conservation of Linear Momentum,

(mg)(vg) = (mb)(vb)

vg = (0.05*60)/10

vg = 0,3m/s

Hence, the speed of recoil of gun is 0.3 m/s

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Explanation: