Question

A bullet of mass 50g is fired from a shotgun of mass 5kg.If the initial velocity
of the bullet is 50m/s, calculate the recoil velocity of the gun.
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Answer 1

Answer:

you know about \text{\underline{conservation of linear momentum}}

conservation of linear momentum

when external force act on system = 0 , linear momentum of system remains constant.

I mean, initial momentum = final momentum

here mass of rifle , M = 5Kg

mass of bullet , m = 50gm = 0.05kg

initial velocity of bullet , u = 50 m/s

we have to find initial recoil velocity of rifle , U

final velocity of bullet , v = 0

final velocity of rifle , V = 0

use conservation of linear momentum,

mu+MU=mv+MVmu+MU=mv+MV

0.05 × 50 + 5 × U = m × 0 + M × 0

0.05 × 50 + 5U = 0

5U = -0.05 × 50

U = -0.5 m/s [here negative sign shows that velocity of rifle is just opposite to the bullet . yes of course it is recoil velocity ]

hence, initial velocity of refile is -0.5 m/s

Explanation:

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Answer 2

50/5=10

10*18/5=36

36*50=1800

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