A bullet of mass 50g is fired horizontally with a velocity 200m/s from a pistol of mass 5kg .calculate the recoil of the pistol
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recoil velocity of the pistol will be =-2m/s
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Answer:
-0.2m/s
Step-by-step explanation:
Using conservation of momentum
mass of bullet × initial velocity of bullet + mass of gun × initial velocity of gun = mass of bullet × final velocity of bullet + mass of gun × final velocity of gun
Since both gun and bullet are at rest, u = 0
0.005(0) + 50(0) = 0.005(200) + 5(x)
0+0 = 1+5x
x = -1/5m/s
x = -0.2m/s
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