Question

a bullet of mass 50g is fired with an initial velocity of 150m/s. if the rifle weights 3kg. what is it's recoil velocity

Answer 1

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Answer 2

Answer:

The recoil velocity of the rifle will be equal to 2.5m/s in the backward direction.

Explanation:

Consider the mass and initial velocity of bullet to be m₁ and u₁ respectively. Also, consider the mass and initial velocity of rifle to be m₂ and v₁ respectively.

We have given, the mass of the bullet, m₁ = 50g

The initial velocity of the bullet, u₁ = 0

The final velocity of the bullet will be, u₂ = 150m/s

The mass of the rifle, m₂ = 3Kg

The recoil velocity of the gun will be v₂ = v

From conservation of linear momentum:

m₁u₁ + m₂v₁ = m₁u₂ + m₂v₂

(50 × 10⁻³Kg)(0)  + (3Kg)(0) = (50×10⁻³Kg)(150m/s) + (3Kg)v

$3v = - 7.5m/s$

$v = -2.5m/s$

Therefore, the recoil velocity of the rifle will be 2.5 m/s in the opposite direction(as the sign is negative).