A bullet of mass 50g is horizontally fired from a pistol of mass 4 kg calculate the recoil velocity of the pistol of the velocity of the bullet is 35 m\s ? class 9
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Accordin to newton's 2nd law,
m1v1=m2v2
Therefore
0.05×35=4×v. (where v is recoil velocity of gun)
v= (0.05*35)/4
v= 0.435 kgm/s
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