Question

A bullet of mass 50g is moved with velocity of 500ms‐¹. It penetrates 10cm into the still target

Answer 1

Answer:

Retarding force

m = 50 g = 50 × 10-3 kg, u = 500 ms-1, s = 10 cm, v = 0

(i) KE = 1/2mv2 = 1/2×50 × 10-3 × (500)2 = 6250 J.

(ii) Using v2 u2 = 2aS, we get

a = {v2 u2}/{2aS} = {02 (500)2}/{2 × 10 ×10-2}

= 1250000ms-2.

Therefore, retarding force, F = ma = 50 × 10-3 × 1250000 = 62500 N. .

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