a bullet of mass 50g is moving with a velocity 500 m/s.It penetrates 10 cm into a still Target and comes to rest.calculate kinetic energy and retarding force offered by the target
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Retarding force
m = 50 g = 50 × 10-3 kg, u = 500 ms-1, s = 10 cm, v = 0
(i) KE = 1/2mv2 = 1/2×50 × 10-3 × (500)2 = 6250 J.
(ii) Using v2 u2 = 2aS, we get
a = {v2 u2}/{2aS} = {02 (500)2}/{2 × 10 ×10-2}
= 1250000ms-2.
Therefore, retarding force, F = ma = 50 × 10-3 × 1250000 = 62500 N
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