A bullet of mass 50g moving with velocity 10m/s collides with a stationary body of mass 950g and gets embedded into it. Loss in kinetic energy is
Answers
Answered by
116
by conservation of momentum : (final velocity of embeded body = mass of bullet × velocity of bullet ÷ mass of bullet + mass of stationary body )
initial kinetc energy is 1/2 × 50 × 10 ×10
final kinetic energy is 1/2 × 50 × final velocity^2
thn loss is k.E = final K.E - initial k.E
initial kinetc energy is 1/2 × 50 × 10 ×10
final kinetic energy is 1/2 × 50 × final velocity^2
thn loss is k.E = final K.E - initial k.E
Answered by
5
Answer:2.375J
Explanation:as
K.E = 1/2 ×(m1×m2/m1+m2) ×(u1-u2)^2
Using this formula we get less in kinetic energy
Similar questions