A bullet of mass 50g travelling with a speed of 15m.s penetrates into a bag of sand and is uniformly brought to rest in 0.05 sec. find (a)How for the bullet Will penetrate into the bag of sand?(b) The average force exerted by the sand.
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Answer:
HEY MATE HERE IS YOUR ANSWER ☺️✌.
Explanation:
GIVEN:
Mass , m= 0.505kg
Initial velocity,u = 500m/s
Distance covered, S = 100 cm = 1 m
Final velocity v = 0
Now , from the equation of motion
v² - u² = 2as
0 - (500)² = 2× a × 1
a = -125000 m/s²
Now , the average force exerted on the block ,
F = ma
F = 0.05 × 125000
F = 6.25 × 10³
_____________________
F = 0.625 × 10⁴N
_______________________
Hence , the average force is 0.625 × 10⁴N .
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