A bullet of mass 5g is fired from a gun with a velocity of 100ms-¹. What is its K.E.? If the barrel of the gun is 80cm long, what force is acted on the bullet by the burnt gas?
Force, Energy and Power (Class X ICSE)
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Answer:
Mass of bullet, m=100g=
1000
100
kg=
10
1
kg
Velocity of bullet, v=100ms
−1
Mass of gun, M=20kg
Let recoil velocity of gun =V
Before firing, the system (gun+bullet) is at rest, therefore, initial momentum of the system =0
Final momentum of the system = momentum of bullet + momentum of gun
=mv+MV=
10
1
×100+20V=10+20V
Applying law of conservation of momentum, Final momentum = Initial momentum
i.e., 10+20V=0
20V=−10
or V=−
20
10
=−0.5ms
−1
.
Negative sign shows that the direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet.
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