Question

a bullet of mass 5g is fired from a pistol of 1.5 kg. If recoil velocity of pistol is 1.5 m/s. Find the velocity of bullet

Answer 1

Mass of bullet = m1 = 5g = 0.005 kg

Mass of pistol = m2 = 1.5 kg

Recoil velocity of pistol = v1 = 1.5 m/s

velocity of bullet = v2 = ?

By conservation of momentum,

m1u1 + m2u2 = m1v1 + m2v2

As , both bullet and gun were at rest during firing, both u1 = u2 = 0 m/s

So,

m1v1 = - m2v2

0.005 × v1 = - 1.5 × 1.5

=> v1 = - (1.5 × 1.5)/0.005

=> v1 = - 450 m/s

Here, negative sign indicates that the bullet went opposite to the direction of recoil of the gun.

Answer 2

$\boxed{ANSWER..}$

Mass of the bullet (m)= 5g

Convert it from gram to kg,

= 5/1000

= 0.005 kg

Mass of the pistol (M)= 1.5Kg

Recoil velocity of the pistol(V) = 1.5m/s

Velocity of the bullet (v) = ?

As we know that ,

V = (-m/M)×v

v = V×M / -m

v = 1.5 × 1.5 / -0.005

v = -450 m/s

Therefore , the velocity of the bullet is -450m/s..