Question

A bullet of mass 5g travels with a speed of 500ms-1
. If it penetrates a fixed target which
offers a constant resistive force of 1000N to the motion of the bullet, calculate
a) The initial kinetic energy of the bullet.
b) The distance through which the bullet has penetrated.

Answer 1

Answer:

kinetic energy = 1/2mv^2

Answer 2

Answer:

mass=5g

speed=500m/s

force=1000N

(a) kinetic energy=

2

1

×m×v×v

m=5g=

1000

5

kg

v=500

⇒

2

1

×

1000

5

×500×500

=625J

(b) force=mass×acceleration

1000=

1000

5

×acceleration

Acceleration=1000×

5

1000

=200000m/s

2

using the third equation of motion

v

2

=u

2

+2as

(500)

2

=0+2×200000×s

250000=400000×s

s=0.625m

I think this is the answer to your question