A bullet of mass 5gm is fired from a pistol of 2kg. If the recoil velocity of the pistol is 2ms-1, find the velocity of the bullet.
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Correct option is
D
500m/s
Conservation of linear momentum gives,
m
1
v
1
+m
2
v
2
=0
m
1
v
1
=−m
2
v
2
v
1
=
m
1
−m
2
v
2
Given, m
1
=10g=(
1000
10
)kg,
m
2
=1 kg,
v
2
=−5m/s
∴v
1
=
10/1000
+1×5
or v
1
=500m/s.
hope its help you
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