A bullet of mass 6.45 g is fired from a 66.0 cm-long rifle barrel at 237 m/s. The mass of the rifle is 4.50 kg. Determine the acceleration of the bullet as well as the recoil acceleration of the rifle.
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Answer:
acceleration time t
0.660 meters = (1/2) a t^2
237 = a t so t = 237/a
then
0.660 = (1/2) a (237^2/a^2)
0.330 a = 237^2
a = 237^2/0.330
momentum is conserved
so
4.50 v rifle = .00645 v bullet at all times
so
a rifle = (.00645/4.50) a bullet
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