Physics, asked by DusyntKml, 9 months ago

A bullet of mass 60 g moving with the velocity of
500 m/s is brought to rest in 0.01 s. Its impulse
will be
(1) 40 Ns
(2) -30 Ns
(3) -20 Ns
(4) +30 Ns​

Answers

Answered by yaswanthlasya
3

Answer:

Explanation:Impulse=mv-mu

= (60/1000)(0-500)

=-30Ns

Option (2).

Answered by udaysharma3784
1

Answer:

-30Ns (2)

Explaination:

Hope it helps you

Attachments:
Similar questions