A bullet of mass 60 g moving with the velocity of
500 m/s is brought to rest in 0.01 s. Its impulse
will be
(1) 40 Ns
(2) -30 Ns
(3) -20 Ns
(4) +30 Ns
Answers
Answered by
3
Answer:
Explanation:Impulse=mv-mu
= (60/1000)(0-500)
=-30Ns
Option (2).
Answered by
1
Answer:
-30Ns (2)
Explaination:
Hope it helps you
Attachments:
Similar questions