A bullet of mass 60g is fired from gun of mass 10kg with a velocity of 60m/s .Calculate the velocity of recoil of the gun .
by using : MV= -mv
Answers
Answered by
6
-0.06*60 = 10 v
v=-0.36 m/s
v=-0.36 m/s
Answered by
8
mass of bullet = 60 g = 0.06 kg
mass of gun = 10 kg
velocity of bullet = 60 m/s
u of bullet = 0
u of gun = 0
Therefore,
m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂
0.06 * 0 + 10 * 0 = 0.06 * 60 m/s + 10v
0 = 3.6 + 10v
-3.6 = 10 v
v = -3.6 / 10 = - 0.36 m/s
Hence the recoil velocity of the gun is 0.36 m/s
mass of gun = 10 kg
velocity of bullet = 60 m/s
u of bullet = 0
u of gun = 0
Therefore,
m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂
0.06 * 0 + 10 * 0 = 0.06 * 60 m/s + 10v
0 = 3.6 + 10v
-3.6 = 10 v
v = -3.6 / 10 = - 0.36 m/s
Hence the recoil velocity of the gun is 0.36 m/s
Similar questions