a bullet of mass 6g travelling at 126ms-1 penetrates into a fixed target and is brought to rest in 0.01 second. determine:-
the distance of penetration in the target
average retarding force exerted on the bullet
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Answered by
10
First we have to find a
a = v-u/0.01 = 126-0/0.01=12600m /s^2
Now s = u^2/2a = 126*126/2*12600=0.63m
F = ma = 0.006*12600=75.6N
a = v-u/0.01 = 126-0/0.01=12600m /s^2
Now s = u^2/2a = 126*126/2*12600=0.63m
F = ma = 0.006*12600=75.6N
Answered by
0
Answer:
75.6
Explanation:
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