Question

a bullet of mass 6g travelling at a speed of 120m/s penetrates into a fixed target and comes to rest in 0.01 secs.calculate​

Answer 1

Answer:

em calculate cheyyali

Answer 2

Answer:

-72 N

Explanation:

Mass = 6 g = 0.006 Kg

Initial speed = 120 m/s

Final speed = 0 m/s

Time taken to change speed = 0.01 s

Change in speed = Final speed - Initial speed = 0 m/s - 120 m/s = - 120 m/s

Acceleration (Deceleration) = Change in speed / Time taken to change speed

                                              = - 120 / 0.01 = - 12000 m/s^2

Force = Mass x Acceleration = - 72 N