Question

A bullet of mass 7 g is fired into a block of metal weighing 7 kg. The block is free to move. After the impact, the velocity of the bullet and the block is 70 m/s. What is the initial velocity of the bullet ?

Answer 1

By considering the conservation of momentum


m1*V1 = (m1+m2)*v


finding V1,after substuting the values


m1= 7g


m2=7000g


v=0.7 m/s


we get V1=700.7 m/s