A bullet of mass 80 g is fired with velocity of 250 m/s from a rifle of mass 5 kg
Calculate the recoil velocity of the rifle. 4 ms.yooon's
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Answers
- Mass of the bullet = 80 g
- Velocity of the bullet = 250 m/s
- Mass of the rifle = 5 kg
- Recoil velocity of the rifle.
Mass of the rifle () = 5 kg
Mass of the bullet () = 80 g = 0.08 kg
We have to find, recoil velocity of the rifle. ()
The bullet is fired with an initial velocity () of 250 m/s
Initially, the rifle is at rest.
Thus, its initial velocity (v) = 0
Total initial momentum of the rifle and bullet :-
⇒ () × v = 0
The total momentum of the rifle and bullet system after firing
=
= (5 × ) + (0.08 × 250)
= 5 + 20
According to the law of conservation of momentum :-
Total momentum after the firing = Total momentum before the firing
So,
5 + 20 = 0
=
= -4 m/s
Recoil velocity of the rifle is -4 m/s.
Hope it helps!!
Given:-
- Mass of bullet = 80 g or 0.08 kg
- Mass of gun = 5 kg
- Velocity of bullet = 250 m/s
To Find:-
- Recoil velocity of rifle.
Solution:-
Here, We know that
Mass of bullet × Velocity of bullet = Mass of Gun × Recoil velocity of gun
⇒ 0.08 kg × 250 m/s = 5 kg × -v m/s
⇒ 20 kg-m/s = -5v kg-m/s
⇒ v = - m/s or -4 m/s
∴ The Recoil Velocity of the rifle is -4 m/s
[Note:- It will negative because it is in opposite direction of firing ]
Some Important Terms:-
- Law of Conservation of Linear momentum:-
Total momentum before collision = Total momentum after collision
that is, m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where, m₁ = mass of first object
m₂ = mass of second object
u₁ = initial velocity of first object
u₂ = initial velocity of second object
v₁ = final velocity of first object
v₂ = final velocity of second object