a bullet of mass A and velocity B is fired into a block of wood of mass C.if loss of any mass and friction be neglected the velocity of system must be
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mass of bullet =A
mass of woden block =C
velocity of bullet= B.
initial momentum of the bullet is m1u1=AB
initial momentum of the wooden block m2u2 =C×0
=0
because block was at rest ,so u=0
____________
therefore final momentum of both m2v2+ m1u1 is( A+C)v
we know that
m1u1 + m2u 2= m1v1 + m2v2
AB+0=V(A+C)
VELOCITY =AB/A+C
Explanation:
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