Question

A bullet of mass A and velocity B is fired into a block of wood of mass C. If loss of any mass and friction be neglected the velocity of system must be...................????

plz ans step by step

Answer 1

mass of bullet =A
mass of woden block =C
velocity of bullet= B.

initial momentum of the bullet is m1u1=AB
initial momentum of the wooden block m2u2 =C×0
=0
bcz block was at rest then u=0
------------------------
therefore final momentum of both m2v2+ m1u1 is( A+C)v

we know that
$m1u1 + m2u 2= m1v1 + m2v2$
AB+0=V(A+C)

VELOCITY =AB/A+C


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