A bullet of mass a and velocity b is fired into a large block of mass c.Then how the final velocity of the system is ab/a+c?
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Answered by
96
Initial momentum of the system=a*b
Final momentum of system=(mass of bullet+mass of large block)*final velocity
=(a+c)*x (x=final velocity)
According to law of conservation of momentum
initial momentum=final momentum
a*b=(a+c)*x
ab/(a+c)=x
Final momentum of system=(mass of bullet+mass of large block)*final velocity
=(a+c)*x (x=final velocity)
According to law of conservation of momentum
initial momentum=final momentum
a*b=(a+c)*x
ab/(a+c)=x
Answered by
9
Because we would consider that the bullet is still stuck inside the block, hence the masses would be added.
1) Initial momentum of the system would be p = mass * velocity = ab
2) Final momentum of the system would be p` = new mass * velocity.
3) Assuming, complete transfer of energy,
new mass = a + c ( mass of block + mass of bullet )
since, the bullet is stuck inside the block.
4) New momentum would be
p` = (a+c) * v`
5) By conservation of momentum :
ab = (a+c) * v`
v` = ab/ (a+c)
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