Question

A bullet of mass A and velocity B is fired into a wooden block of mass C. If the bullet gets embedds
in the wooden block, then the magnitude of velocity of the system just after the collision will be
AR
А+ С​

Answer 1

Answer:

$\frac{AB}{A+C}$

Explanation:

Given:

(Mass) bullet =A

(Velocity) bullet=B

(Mass) block=C

(Velocity) block=0

Momentum before impact = Momentum after impact

AB+0=(A+C)(v) system

(v) system = $\frac{AB}{A+C}$

​

The velocity of the system (v) system = $\frac{AB}{A+C}$

:)

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