A bullet of mass A and velocity B is fired into a wooden block of mass C. If the bullet gets embedded in the wooden block, then what will be the magnitude of velocity of the system just after the collision??
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Answer:
AB/A+C
Explanation:
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2
Given:
The bullet strikes the block and after collision they become a system and
(Mass)bullet=A
(Velocity)bullet=B
(Mass)block=C
(Velocity)block=0
Momentum before impact = Momentum after impact
AB+0=(A+C)(v)system
(v)system=A+CAB
The velocity of the system (v)system=A+CAB
Refer to attachment!!
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